JS基础题,却有多少人能弄清楚其中的奥义?
发布于 7 年前 作者 fattypiggy 4760 次浏览 来自 问答

let data = [1,2,3], i = 0;
data[i++] = data[i++]*2;

问这个操作之后,data数组为多少?i的值是多少?(各1分) 为什么?(98分)

17 回复

😁我就是标题党!吸引老司机来解答我的问题

我做错了 233,我以为是 [2,2,3] 和 2…

这是 C 语言的遗毒啊,没什么好弄清楚的,永远不要写这种代码。还是我来出题吧。 下面这段简单的代码,却有多少人能弄清楚其中的奥义?(-1w分)

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这段浅显的代码,谁又了解个中的深意?(-10086分)

゚ω゚ノ= /`m´)ノ ~┻━┻   //*´∇`*/ ['_']; o=(゚ー゚)  =_=3; c=(゚Θ゚) =(゚ー゚)-(゚ー゚); (゚Д゚) =(゚Θ゚)= (o^_^o)/ (o^_^o);(゚Д゚)={゚Θ゚: '_' ,゚ω゚ノ : ((゚ω゚ノ==3) +'_') [゚Θ゚] ,゚ー゚ノ :(゚ω゚ノ+ '_')[o^_^o -(゚Θ゚)] ,゚Д゚ノ:((゚ー゚==3) +'_')[゚ー゚] }; (゚Д゚) [゚Θ゚] =((゚ω゚ノ==3) +'_') [c^_^o];(゚Д゚) ['c'] = ((゚Д゚)+'_') [ (゚ー゚)+(゚ー゚)-(゚Θ゚) ];(゚Д゚) ['o'] = ((゚Д゚)+'_') [゚Θ゚];(゚o゚)=(゚Д゚) ['c']+(゚Д゚) ['o']+(゚ω゚ノ +'_')[゚Θ゚]+ ((゚ω゚ノ==3) +'_') [゚ー゚] + ((゚Д゚) +'_') [(゚ー゚)+(゚ー゚)]+ ((゚ー゚==3) +'_') [゚Θ゚]+((゚ー゚==3) +'_') [(゚ー゚) - (゚Θ゚)]+(゚Д゚) ['c']+((゚Д゚)+'_') [(゚ー゚)+(゚ー゚)]+ (゚Д゚) ['o']+((゚ー゚==3) +'_') [゚Θ゚];(゚Д゚) ['_'] =(o^_^o) [゚o゚] [゚o゚];(゚ε゚)=((゚ー゚==3) +'_') [゚Θ゚]+ (゚Д゚) .゚Д゚ノ+((゚Д゚)+'_') [(゚ー゚) + (゚ー゚)]+((゚ー゚==3) +'_') [o^_^o -゚Θ゚]+((゚ー゚==3) +'_') [゚Θ゚]+ (゚ω゚ノ +'_') [゚Θ゚]; (゚ー゚)+=(゚Θ゚); (゚Д゚)[゚ε゚]='\\'; (゚Д゚).゚Θ゚ノ=(゚Д゚+ ゚ー゚)[o^_^o -(゚Θ゚)];(o゚ー゚o)=(゚ω゚ノ +'_')[c^_^o];(゚Д゚) [゚o゚]='\"';(゚Д゚) ['_'] ( (゚Д゚) ['_'] (゚ε゚+(゚Д゚)[゚o゚]+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ (゚ー゚)+ (o^_^o)+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ ((゚ー゚) + (o^_^o))+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ ((o^_^o) +(o^_^o))+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((o^_^o) +(o^_^o))+ (o^_^o)+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ ((゚ー゚) + (o^_^o))+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ (゚ー゚)+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ (゚ー゚)+ ((゚ー゚) + (゚Θ゚))+ (゚Д゚)[゚ε゚]+((゚ー゚) + (゚Θ゚))+ ((o^_^o) +(o^_^o))+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ (゚ー゚)+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ ((゚ー゚) + (゚Θ゚))+ ((゚ー゚) + (o^_^o))+ (゚Д゚)[゚ε゚]+(゚Θ゚)+ (゚ー゚)+ ((゚ー゚) + (o^_^o))+ (゚Д゚)[゚ε゚]+((゚ー゚) + (゚Θ゚))+ (c^_^o)+ (゚Д゚)[゚ε゚]+((o^_^o) +(o^_^o))+ ((o^_^o) +(o^_^o))+ (゚Д゚)[゚ε゚]+((o^_^o) +(o^_^o))+ ((o^_^o) +(o^_^o))+ (゚Д゚)[゚ε゚]+((o^_^o) +(o^_^o))+ ((o^_^o) +(o^_^o))+ (゚Д゚)[゚ε゚]+((゚ー゚) + (゚Θ゚))+ (゚Θ゚)+ (゚Д゚)[゚o゚]) (゚Θ゚)) ('_');

这种题有个p用,谁写开除谁

我只是在想,到底要什么样的情况才能遇到这种代码呢

有什么意义吗

你知道回字有多少种写法不?

@leavesdrift 为啥是[4,2,3],昨晚看犀牛书上的问题,自己也不知道所以试了试。

回复楼上所有:我不是想问这个题目答案是什么,也并不好奇回字有多少种写法,只是想知道一下这种运算顺序。这种代码肯定是不能用在项目中的,单纯的问一下运算顺序,你知道就回答我,不知道就找个凉快地方待一会?

i++与++i的问题

下面那个实际为:data[0] = data[1] * 2 所以最后就是[4,2,3]

不想回答你估计是因为你这标题起得不好

@linliny data[0]=data[1]*2;

看到谁写开除谁,我就放心多了,因为我也不会呀

data[i++]:先data[i],再i++

找个凉快地方待一会

找个凉快地方边吃瓜边待一会

这道题的运算方式解出来是这样的 let data = [1,2,3], i = 0; let index1=i; i++; let index2=i; i++; data[index1]=data[index2]*2; 所以运算顺序是括号优先级最大,两个括号之间,等号左边的大于等号右边的 仔细想一想其实符合运算逻辑

但是++这个运算为什么在括号之外就不知道了

可以通过语法树看一下就明白了,我只是不知道prefix=false指的是什么意思 语法树解析:https://astexplorer.net/

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