我想问一下，怎么直接暴露JSON.

新浪API返回的JSON

{
    ret: 1,
    start: -1,
    end: -1,
    country: '中国',
    province: '上海',
    city: '上海',
    district: '',
    isp: '',
    type: '',
    desc: ''
}

node代码

class IP {
    constructor(){
        this.name = 'IPAPI';
    };
    getIpInfo(ip, cb){
        let options = {
            host: 'int.dpool.sina.com.cn',
            path: `/iplookup/iplookup.php?format=json&ip=${ip}`,
            method: 'get'
        };
        http.request(options, (response) => {
            var data = '';
            response.on('data',(chunk) => {
                data+= chunk;
            }).on('end', function () {
                data = JSON.parse(data);
                data.ip = ip;
                this.data = data;
                cb(null,data);
            }).on('error',function(){
                cb(null, {status:'Error!'});
            })
        }).end();
    }
}

这个JSON目前只能通过回调方式获取.

let ip = new IP();
ip.getIpInfo('180.157.199.109', (err,data) => { 
    console.log(data);
	// data = JSON
});

我想改成

let ip = new IP();
console.log(ip.getIpInfo('180.157.199.109');)
//ip.getIpInfo = JSON;

这样!