459560
var testInsertAndUpdate = function (conn,cb) {
conn.execute(
"SELECT age FROM test WHERE id LIKE 1 ",
function a (err, result)
{
if (err) {
return cb(err, conn);
} else {
console.log ("----- Select Test --------");
cute = result.rows;
console.log ('cute:'+cute);
return cb(null, conn);
}
});
};
输出 cute:13 我想在另一个函数的if语句中调用cute的值 if (cute !== null) { }