项目遇到了js递归的问题,不知道怎么解
发布于 9 个月前 作者 xue99999 1139 次浏览 来自 问答

问题1,colorArr 的第N项添加到data的第N项及其子元素,子元素的子元素

var colorArr = ['orange', 'green']
var data = [{
  name: 'a',
  children: [{
    name: 'a1',
    children: [{
      name: 'aa1'
    }]
  }]
}, {
  name: 'b',
  children: [{
    name: 'b1'
  }]
}]

期待的结果

[{
  name: 'a',
  color: 'orange',
  children: [{
    name: 'a1',
    color: 'orange'
    children: [{
      name: 'aa1',
      color: 'orange'
    }]
  }]
}, {
  name: 'b',
  color: 'green',
  children: [{
    name: 'b1',
    color: 'green'
  }]
}]

问题2,根据最后一层子元素的value值,计算出他父元素的value值,以及父元素的父元素的value值,一直计算到最上层的value值

var data = [{
  name: 'a',
  children: [{
    name: 'a1',
    children: [{
      name: 'aa1',
      value: 1
    }, {
      name: 'aa2',
      value: 1
    }]
  }, {
    name: 'a11',
    children: [{
      name: 'aAA',
      value: 2
    }]
  }]
}, {
  name: 'b',
  children: [{
    name: 'b1',
    value:3
  }]
}]

期待的结果

var data = [{
  name: 'a',
  value: 4,
  children: [{
    name: 'a1',
    value: 2,
    children: [{
      name: 'aa1',
      value: 1
    }, {
      name: 'aa2',
      value: 1
    }]
  }, {
    name: 'a11',
    value: 2,
    children: [{
      name: 'aAA',
      value: 2
    }]
  }]
}, {
  name: 'b',
  value: 3,
  children: [{
    name: 'b1',
    value:3
  }]
}]
5 回复

自己顶一下,第一道题我自己解决了,第二题尚未解决,大家对这个没兴趣嘛

后序遍历,算出所有孩子的value,再算出父亲的value,直到根

function traversal(node) {
    if (node.children && node.children.length) {
        let ret = 0;
        for (let i = 0; i < node.children.length; i++) {
            traversal(node.children[i]);
            ret += node.children[i].value;
        }
        node.value = ret;
    }
}

@theanarkh 谢谢大佬,原来不是递归能解决的问题了,我去看看后序遍历

随便写写,自己优化一下

var data = [
  {
    name: "a",
    children: [
      {
        name: "a1",
        children: [
          {
            name: "aa1",
            value: 1,
          },
          {
            name: "aa2",
            value: 1,
          },
        ],
      },
      {
        name: "a11",
        children: [
          {
            name: "aAA",
            value: 2,
          },
        ],
      },
    ],
  },
  {
    name: "b",
    children: [
      {
        name: "b1",
        value: 3,
      },
    ],
  },
];

var computed = (list) => {
  let count = 0;
  for (const item of list) {
    if (item.children) {
      item.value = computed(item.children);
    }
    count += item.value;
  }
  return count;
};
computed(data);
console.log(data);
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